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Popular >

simplify x_{1}[n]^*x_{2}[n]

Solution

simplify

x_{1} [n]^{\cdot} x_{2} [n]

Solution

x_{1} x_{2} (n)^{2}

Solution steps

x_{1} [n] x_{2} [n]

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

[n] [n] = ([n])^{1 + 1}

= x_{1} x_{2} ([n])^{1 + 1}

Add the numbers:

1 + 1 = 2

= x_{1} x_{2} ([n])^{2}

Remove parentheses:

(a) = a

= x_{1} x_{2} (n)^{2}

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Frequently Asked Questions (FAQ)

What is x_{1}[n]^*x_{2}[n] ?
The solution to x_{1}[n]^*x_{2}[n] is x_{1}x_{2}(n)^2