What is sqrt(3^{3x-1=3^{x+4)}} ?

The solution to sqrt(3^{3x-1=3^{x+4)}} is 3^{1/2 (3x-1=3^{x+4})}

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simplify sqrt(3^{3x-1=3^{x+4)}}

simplify

3^{3 x - 1 = 3^{x + 4}}

3^{\frac{1}{2} (3 x - 1 = 3^{x + 4})}

Solution steps

3^{3 x - 1 = 3^{x + 4}}

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{3 x - 1 = 3^{x + 4}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{(3 x - 1 = 3^{x + 4}) \frac{1}{2}}

1.33 \cdot 1 0^{- 8}

e^{- 2 x} x^{6}

2 e^{- 1} \cdot (3 e^{3})^{2}

x (5 x^{3})

What is sqrt(3^{3x-1=3^{x+4)}} ?
The solution to sqrt(3^{3x-1=3^{x+4)}} is 3^{1/2 (3x-1=3^{x+4})}