What are the solutions to the equation 42=d^2-22 ?

The solutions to the equation 42=d^2-22 are d=8,d=-8

Find the zeros of 42=d^2-22

The zeros of 42=d^2-22 are d=8,d=-8

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42 = d^{2} - 22

d = 8, d = - 8

Solution steps

42 = d^{2} - 22

Switch sides

d^{2} - 22 = 42

Move

22

to the right side

d^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 64, d = - 64

64 = 8

- 64 = - 8

d = 8, d = - 8

4 x^{2} + 4 x - 24

- 6 x^{2} = - 96

∣ x - 3 ∣ < 0

lo g_{2} (lo g_{4} (x^{2} - 4 x - 5)) < 0

6 \geq 6 x

What are the solutions to the equation 42=d^2-22 ?
The solutions to the equation 42=d^2-22 are d=8,d=-8
Find the zeros of 42=d^2-22
The zeros of 42=d^2-22 are d=8,d=-8