What is e^{-2(-t+1)}u(-t+1) ?

The solution to e^{-2(-t+1)}u(-t+1) is (u(-t+1))/(e^{2(-t+1))}

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simplify e^{-2(-t+1)}u(-t+1)

simplify

e^{- 2 (- t + 1)} u (- t + 1)

\frac{u ( - t + 1 )}{e ^{2 (- t + 1)}}

Solution steps

e^{- 2 (- t + 1)} u (- t + 1)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 (- t + 1)}} u (- t + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot u ( - t + 1 )}{e ^{2 (- t + 1)}}

Multiply:

1 \cdot u = u

= \frac{u ( - t + 1 )}{e ^{2 (- t + 1)}}

2.75 \cdot 1 0^{- 3}

- e^{- \frac{0}{5}}

1 0^{- 2} 0.3

What is e^{-2(-t+1)}u(-t+1) ?
The solution to e^{-2(-t+1)}u(-t+1) is (u(-t+1))/(e^{2(-t+1))}