What is (x^2-3xy+y^2)(4x^2y^2) ?

The solution to (x^2-3xy+y^2)(4x^2y^2) is 4x^2y^2(x^2-3xy+y^2)

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simplify (x^2-3xy+y^2)(4x^2y^2)

simplify

(x^{2} - 3 x y + y^{2}) (4 x^{2} y^{2})

4 x^{2} y^{2} (x^{2} - 3 x y + y^{2})

Solution steps

(x^{2} - 3 x y + y^{2}) (4 x^{2} y^{2})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} y^{2} = (x y)^{2}

= 4 (x^{2} - 3 x y + y^{2}) (x y)^{2}

(x y)^{2} = x^{2} y^{2}

= 4 x^{2} y^{2} (x^{2} - 3 x y + y^{2})

(t^{2}) e^{(- a \cdot t)}

(x^{2} y) (x y^{3})

0.83 \cdot 1 0^{- 12}

7 \cdot e^{- 93 \cdot 34}

(4 - 2 (- 1)) e^{- 1}

What is (x^2-3xy+y^2)(4x^2y^2) ?
The solution to (x^2-3xy+y^2)(4x^2y^2) is 4x^2y^2(x^2-3xy+y^2)