What is [(b^{-2})^3]^{-2} ?

The solution to [(b^{-2})^3]^{-2} is b^{12}

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simplify [(b^{-2})^3]^{-2}

simplify

[(b^{- 2})^{3}]^{- 2}

b^{12}

Solution steps

[(b^{- 2})^{3}]^{- 2}

(b^{- 2})^{3} : b^{- 6}

= [b^{- 6}]^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( b ^{- 6} ) ^{2}}

(b^{- 6})^{2} : b^{- 12}

= \frac{1}{b ^{- 12}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

b^{- 12} = \frac{1}{b ^{12}}

= \frac{1}{\frac{1}{b ^{12}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{12}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= b^{12}

2 (5 a^{2}) (7 b^{2})

((- 3)^{3})^{5}

e^{- (0.5 + (- 0.5))}

(- 45.9) (1 - 105.97)^{- 2}