What is (1+sin(2pit))e^{-t/(10)} ?

The solution to (1+sin(2pit))e^{-t/(10)} is (sin(2pit)+1)/(e^{t/(10))}

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simplify (1+sin(2pit))e^{-t/(10)}

simplify

(1 + sin (2 π t)) e^{- \frac{t}{10}}

\frac{sin ( 2 π t ) + 1}{e ^{\frac{t}{10}}}

Solution steps

(1 + sin (2 π t)) e^{- \frac{t}{10}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{\frac{t}{10}}} (sin (2 π t) + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 1 + sin ( 2 π t ) )}{e ^{\frac{t}{10}}}

1 \cdot (1 + sin (2 π t)) = 1 + sin (2 π t)

= \frac{1 + sin ( 2 π t )}{e ^{\frac{t}{10}}}

70 (300)^{- 0.25}

4.1 \cdot 1 0^{- 12}

e^{x} \cdot e^{c}

x^{m + 1} y^{m + 1}

39.3 \cdot 1 0^{- 3}

What is (1+sin(2pit))e^{-t/(10)} ?
The solution to (1+sin(2pit))e^{-t/(10)} is (sin(2pit)+1)/(e^{t/(10))}