What is x^2(2x+8)(x-2)(x-5)^2 ?

The solution to x^2(2x+8)(x-2)(x-5)^2 is x^2(x-5)^2(x-2)(2x+8)

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simplify x^2(2x+8)(x-2)(x-5)^2

simplify

x^{2} (2 x + 8) (x - 2) (x - 5)^{2}

x^{2} (x - 5)^{2} (x - 2) (2 x + 8)

Solution steps

x^{2} (2 x + 8) (x - 2) (x - 5)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} (x - 5)^{2} = (x (x - 5))^{2}

= (x (x - 5))^{2} (2 x + 8) (x - 2)

(x (x - 5))^{2} = x^{2} (x - 5)^{2}

= x^{2} (x - 5)^{2} (2 x + 8) (x - 2)

x^{13} (e^{x})^{7}

(3 y^{5}) (4 y^{9})

3.6788 \cdot 1 0^{- 7}

e^{- \frac{10}{5}}

What is x^2(2x+8)(x-2)(x-5)^2 ?
The solution to x^2(2x+8)(x-2)(x-5)^2 is x^2(x-5)^2(x-2)(2x+8)