What is e^{-(-ln(4/6))^{0.5}} ?

The solution to e^{-(-ln(4/6))^{0.5}} is 1/(e^{(-ln(2/3))^{1/2)}}

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simplify e^{-(-ln(4/6))^{0.5}}

simplify

e^{- (- l n (\frac{4}{6}))^{0.5}}

\frac{1}{e ^{(- l n (\frac{2}{3}))^{\frac{1}{2}}}}

Decimal Notation

0.52900 \dots

Solution steps

e^{- (- l n (\frac{4}{6}))^{0.5}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(- l n (\frac{4}{6}))^{0.5}}}

e^{(- l n (\frac{4}{6}))^{\frac{1}{2}}} = e^{(- l n (\frac{2}{3}))^{\frac{1}{2}}}

= \frac{1}{e ^{(- l n (\frac{2}{3}))^{\frac{1}{2}}}}

60 π \cdot 3 \cdot 1 0^{- 3}

8.653 x 1 0^{- 17}

8 \cdot 1.6 \cdot 1 0^{- 19}

e^{- 6 l n (2)}

What is e^{-(-ln(4/6))^{0.5}} ?
The solution to e^{-(-ln(4/6))^{0.5}} is 1/(e^{(-ln(2/3))^{1/2)}}