What is (-x-4)^2(x+1)^2(x-5) ?

The solution to (-x-4)^2(x+1)^2(x-5) is (x+1)^2(x-5)(-x-4)^2

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simplify (-x-4)^2(x+1)^2(x-5)

simplify

(- x - 4)^{2} (x + 1)^{2} (x - 5)

(x + 1)^{2} (x - 5) (- x - 4)^{2}

Solution steps

(- x - 4)^{2} (x + 1)^{2} (x - 5)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(- x - 4)^{2} (x + 1)^{2} = ((- x - 4) (x + 1))^{2}

= ((- x - 4) (x + 1))^{2} (x - 5)

((- x - 4) (x + 1))^{2} = (- x - 4)^{2} (x + 1)^{2}

= (- x - 4)^{2} (x + 1)^{2} (x - 5)

e^{- x} \cdot x^{- 1}

6.6 \cdot 1 0^{- 10}

(5 x^{3} y^{2}) (5 x^{3} y^{4})

1.2043 \cdot 1 0^{- 7}

2 t

What is (-x-4)^2(x+1)^2(x-5) ?
The solution to (-x-4)^2(x+1)^2(x-5) is (x+1)^2(x-5)(-x-4)^2