What are the solutions to the equation x(x-4)=140 ?

The solutions to the equation x(x-4)=140 are x=14,x=-10

Find the zeros of x(x-4)=140

The zeros of x(x-4)=140 are x=14,x=-10

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x (x - 4) = 140

x = 14, x = - 10

Solution steps

x (x - 4) = 140

Expand

x (x - 4) : x^{2} - 4 x

x^{2} - 4 x = 140

Move

140

to the left side

x^{2} - 4 x - 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 140 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 140) = 24

x_{1, 2} = \frac{- ( - 4 ) \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 24}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 24}{2 \cdot 1}

x = \frac{- ( - 4 ) + 24}{2 \cdot 1} : 14

x = \frac{- ( - 4 ) - 24}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 14, x = - 10

- \frac{5}{8} \cdot \frac{2}{3}

(3 x + 2)^{2} = 15

lo g_{5} (- 2)

- 16 + 5 x \geq 19

- 2 (4 x - 5) + 2 x + 4 = 26

What are the solutions to the equation x(x-4)=140 ?
The solutions to the equation x(x-4)=140 are x=14,x=-10
Find the zeros of x(x-4)=140
The zeros of x(x-4)=140 are x=14,x=-10