What is (x+1)(2x-3)>= (x+1)(x-3) ?

The solution to (x+1)(2x-3)>= (x+1)(x-3) is x = 0

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(x+1)(2x-3)>= (x+1)(x-3)

(x + 1) (2 x - 3) \geq (x + 1) (x - 3)

x \leq - 1 or x \geq 0

Interval Notation

(- \infty, - 1] \cup [0, \infty)

Solution steps

(x + 1) (2 x - 3) \geq (x + 1) (x - 3)

Rewrite in standard form

x^{2} + x \geq 0

Factor

x^{2} + x : x (x + 1)

x (x + 1) \geq 0

Identify the intervals

x \leq - 1 or x \geq 0

17 + \frac{- 18}{6}

(m + 3) + 0.7 \geq - 0.3 (- m + \frac{1}{4})

16 x^{2} - 100

7 y^{2} + 19 y + 10

\frac{4 !}{3 !}

What is (x+1)(2x-3)>= (x+1)(x-3) ?
The solution to (x+1)(2x-3)>= (x+1)(x-3) is x<=-1\lor x>= 0