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Popular >

simplify e^{-ln(1+y)}

Solution

simplify

e^{- l n (1 + y)}

Solution

\frac{1}{y + 1}

Solution steps

e^{- l n (1 + y)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (1 + y)}}

e^{l n (1 + y)} = 1 + y

= \frac{1}{1 + y}

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Frequently Asked Questions (FAQ)

What is e^{-ln(1+y)} ?
The solution to e^{-ln(1+y)} is 1/(y+1)