What is (f^{-1}\circ g^{-1})(1) ?

The solution to (f^{-1}\circ g^{-1})(1) is (\circ)/(fg)

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simplify (f^{-1}\circ g^{-1})(1)

simplify

(f^{- 1} \circ g^{- 1}) (1)

\frac{\circ}{f g}

Solution steps

(f^{- 1} \circ g^{- 1}) (1)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

f^{- 1} g^{- 1} = (f g)^{- 1}

= 1 \circ (f g)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(f g)^{- 1} = \frac{1}{f g}

= 1 \circ \frac{1}{f g}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 1 \cdot \frac{1 \circ}{f g}

Refine

= \frac{\circ}{f g}

ln (α β x^{β - 1}) (e^{- α x^{β}})

9 (1.05)^{- (- 8)}

- 1.602 x 1 0^{- 19}

(j - 1)^{2} (j + 1)^{2}

8.35 \cdot 1 0^{- 4}

What is (f^{-1}\circ g^{-1})(1) ?
The solution to (f^{-1}\circ g^{-1})(1) is (\circ)/(fg)