What is (1.6x10^{-19})(3712) ?

The solution to (1.6x10^{-19})(3712) is (5939.2x)/(10^{19)}

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simplify (1.6x10^{-19})(3712)

simplify

(1.6 x 1 0^{- 19}) (3712)

\frac{5939.2 x}{1 0 ^{19}}

Solution steps

(1.6 x \cdot 1 0^{- 19}) (3712)

Apply rule:

(a) = a

(3712) = 3712

= 1.6 x \cdot 1 0^{- 19} \cdot 3712

Multiply the numbers:

1.6 \cdot 3712 = 5939.2

= 5939.2 x \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 5939.2 x

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 5939.2 x

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 5939.2 x}{1 0 ^{19}}

Multiply the numbers:

1 \cdot 5939.2 = 5939.2

= \frac{5939.2 x}{1 0 ^{19}}

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What is (1.6x10^{-19})(3712) ?
The solution to (1.6x10^{-19})(3712) is (5939.2x)/(10^{19)}