What are the solutions to the equation w^2-10w+40=0 ?

The solutions to the equation w^2-10w+40=0 are w=5+sqrt(15)i,w=5-sqrt(15)i

Find the zeros of w^2-10w+40=0

The zeros of w^2-10w+40=0 are w=5+sqrt(15)i,w=5-sqrt(15)i

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w^{2} - 10 w + 40 = 0

w = 5 + 15 i, w = 5 - 15 i

Solution steps

w^{2} - 10 w + 40 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 40 : 215 i

w_{1, 2} = \frac{- ( - 10 ) \pm 2 15 i}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 10 ) + 2 15 i}{2 \cdot 1}, w_{2} = \frac{- ( - 10 ) - 2 15 i}{2 \cdot 1}

w = \frac{- ( - 10 ) + 2 15 i}{2 \cdot 1} : 5 + 15 i

w = \frac{- ( - 10 ) - 2 15 i}{2 \cdot 1} : 5 - 15 i

The solutions to the quadratic equation are:

w = 5 + 15 i, w = 5 - 15 i

\frac{- 8}{- 2}

2 x^{2} - 5 x < - 3

- x^{2} + 6 x = 8

- 4 (x + 8) - 2 x = 25

- - 80

What are the solutions to the equation w^2-10w+40=0 ?
The solutions to the equation w^2-10w+40=0 are w=5+sqrt(15)i,w=5-sqrt(15)i
Find the zeros of w^2-10w+40=0
The zeros of w^2-10w+40=0 are w=5+sqrt(15)i,w=5-sqrt(15)i