What are the solutions to the equation 4w^2=-12w ?

The solutions to the equation 4w^2=-12w are w=0,w=-3

Find the zeros of 4w^2=-12w

The zeros of 4w^2=-12w are w=0,w=-3

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4 w^{2} = - 12 w

w = 0, w = - 3

Solution steps

4 w^{2} = - 12 w

Move

12 w

to the left side

4 w^{2} + 12 w = 0

Factor

4 w^{2} + 12 w : 4 w (w + 3)

4 w (w + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

w = 0 or w + 3 = 0

Solve

w + 3 = 0 : w = - 3

The solutions to the quadratic equation are:

w = 0, w = - 3

2 - \frac{13}{2}

(\frac{1}{64})^{- \frac{2}{3}}

(3 a^{- 2})^{3} (a^{3})^{- 4}

x \cdot x^{- \frac{1}{9}}

x^{2} - 8 x \geq - 12

What are the solutions to the equation 4w^2=-12w ?
The solutions to the equation 4w^2=-12w are w=0,w=-3
Find the zeros of 4w^2=-12w
The zeros of 4w^2=-12w are w=0,w=-3