What are the solutions to the equation x^2+147=0 ?

The solutions to the equation x^2+147=0 are x=sqrt(3)*7i,x=-sqrt(3)*7i

Find the zeros of x^2+147=0

The zeros of x^2+147=0 are x=sqrt(3)*7i,x=-sqrt(3)*7i

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x^{2} + 147 = 0

x = 3 \cdot 7 i, x = - 3 \cdot 7 i

Solution steps

x^{2} + 147 = 0

Move

147

to the right side

x^{2} = - 147

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 147, x = - - 147

- 147 = 3 \cdot 7 i

- - 147 = - 3 \cdot 7 i

x = 3 \cdot 7 i, x = - 3 \cdot 7 i

- 381 + 16

7 - ∣ 3 x + 9 ∣ = 1

23 x^{4} y z^{5} - 6 z^{3}

6 x^{2} = 6 - 5 x

9 + x = 2 - 5 x

What are the solutions to the equation x^2+147=0 ?
The solutions to the equation x^2+147=0 are x=sqrt(3)*7i,x=-sqrt(3)*7i
Find the zeros of x^2+147=0
The zeros of x^2+147=0 are x=sqrt(3)*7i,x=-sqrt(3)*7i