What is simplify-16(2x+1)^2(x-2)^2(x-4) ?

The solution to simplify-16(2x+1)^2(x-2)^2(x-4) is -16(x-2)^2(x-4)(2x+1)^2

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simplify-16(2x+1)^2(x-2)^2(x-4)

simplify

- 16 (2 x + 1)^{2} (x - 2)^{2} (x - 4)

- 16 (x - 2)^{2} (x - 4) (2 x + 1)^{2}

Solution steps

- 16 (2 x + 1)^{2} (x - 2)^{2} (x - 4)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(2 x + 1)^{2} (x - 2)^{2} = ((2 x + 1) (x - 2))^{2}

= - 16 ((2 x + 1) (x - 2))^{2} (x - 4)

((2 x + 1) (x - 2))^{2} = (2 x + 1)^{2} (x - 2)^{2}

= - 16 (2 x + 1)^{2} (x - 2)^{2} (x - 4)

e^{(- 1439. 1^{- 2})}

e^{- 1000000000}

8.72 x 1 0^{- 10}

9.35 x 1 0^{- 4}

What is simplify-16(2x+1)^2(x-2)^2(x-4) ?
The solution to simplify-16(2x+1)^2(x-2)^2(x-4) is -16(x-2)^2(x-4)(2x+1)^2