What is e^{-at}sin(wt)*u(t-1) ?

The solution to e^{-at}sin(wt)*u(t-1) is (usin(tw)(t-1))/(e^{at)}

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simplify e^{-at}sin(wt)*u(t-1)

simplify

e^{- a t} sin (wt) \cdot u (t - 1)

\frac{u sin ( tw ) ( t - 1 )}{e ^{a t}}

Solution steps

e^{- a t} sin (wt) u (t - 1)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{a t}} u sin (tw) (t - 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( wt ) u ( t - 1 )}{e ^{a t}}

Multiply:

1 \cdot sin (wt) = sin (wt)

= \frac{u sin ( tw ) ( t - 1 )}{e ^{a t}}

e^{- 50} (1 - 50)

60 \cdot e^{(- 0.538 \cdot 5.25)}

\frac{- 49}{- 7}

e^{- l n (x^{12})}

7.648 \cdot 1 0^{- 2}

What is e^{-at}sin(wt)*u(t-1) ?
The solution to e^{-at}sin(wt)*u(t-1) is (usin(tw)(t-1))/(e^{at)}