What is sqrt((2-10)^{2^')} ?

The solution to sqrt((2-10)^{2^')} is (-8)^{2^{'-1}}

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simplify sqrt((2-10)^{2^')}

simplify

(2 - 10)^{2^{^{'}}}

(- 8)^{2^{' - 1}}

Solution steps

(2 - 10)^{2^{^{'}}}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((2 - 10)^{2^{^{^{'}}}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (2 - 10)^{2^{^{^{'}}} \cdot \frac{1}{2}}

Simplify

2^{^{'}} \cdot \frac{1}{2} : 2^{^{'} - 1}

= (2 - 10)^{2^{^{'} - 1}}

Subtract the numbers:

2 - 10 = - 8

= (- 8)^{2^{^{^{'}} - 1}}

1.1 \cdot 1 0^{- 15}

m^{2} (8 n + 7)^{2}

36 - x^{2} x + 3

1 0^{- 3}

36 - x^{2} x + 2

What is sqrt((2-10)^{2^')} ?
The solution to sqrt((2-10)^{2^')} is (-8)^{2^{'-1}}