What is (1+x^2)^2*(1-3x)^2 ?

The solution to (1+x^2)^2*(1-3x)^2 is (-3x+1)^2(x^2+1)^2

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simplify (1+x^2)^2*(1-3x)^2

simplify

(1 + x^{2})^{2} \cdot (1 - 3 x)^{2}

(- 3 x + 1)^{2} (x^{2} + 1)^{2}

Solution steps

(1 + x^{2})^{2} (1 - 3 x)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} + 1)^{2} (- 3 x + 1)^{2} = ((x^{2} + 1) (- 3 x + 1))^{2}

= ((x^{2} + 1) (- 3 x + 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x^{2} + 1)^{2} (- 3 x + 1)^{2}

6 (x^{2} + 4)^{2} (x - 4)^{2}

e^{- l n (2)}

3. 5^{2} e^{- 3.5}

- 3 (3 x^{2})

What is (1+x^2)^2*(1-3x)^2 ?
The solution to (1+x^2)^2*(1-3x)^2 is (-3x+1)^2(x^2+1)^2