What are the solutions to the equation 2x+6=x^2-3x ?

The solutions to the equation 2x+6=x^2-3x are x=6,x=-1

Find the zeros of 2x+6=x^2-3x

The zeros of 2x+6=x^2-3x are x=6,x=-1

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2 x + 6 = x^{2} - 3 x

x = 6, x = - 1

Solution steps

2 x + 6 = x^{2} - 3 x

Switch sides

x^{2} - 3 x = 2 x + 6

Move

6

to the left side

x^{2} - 3 x - 6 = 2 x

Move

2 x

to the left side

x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

x = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

b^{4} (\frac{1}{3} b^{2}) (12 b^{- 8})

∣ x ∣ = 49

\frac{2 π}{\frac{2}{3}}

t^{2} + 2 t = 0

21.3 \cdot \frac{1}{137.33} \cdot \frac{1}{3} \cdot \frac{26.98}{1}

What are the solutions to the equation 2x+6=x^2-3x ?
The solutions to the equation 2x+6=x^2-3x are x=6,x=-1
Find the zeros of 2x+6=x^2-3x
The zeros of 2x+6=x^2-3x are x=6,x=-1