What is e^{-at}t^{n-1} 1/(n!) ?

The solution to e^{-at}t^{n-1} 1/(n!) is (t^{n-1})/(e^{at)n!}

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simplify e^{-at}t^{n-1} 1/(n!)

simplify

e^{- a t} t^{n - 1} \frac{1}{n !}

\frac{t ^{n - 1}}{e ^{a t} n !}

Solution steps

e^{- a t} t^{n - 1} \frac{1}{n !}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{n !} \cdot \frac{1}{e ^{a t}} t^{n - 1}

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 1 \cdot t ^{n - 1}}{e ^{a t} n !}

Multiply:

1 \cdot 1 \cdot t^{n - 1} = t^{n - 1}

= \frac{t ^{n - 1}}{e ^{a t} n !}

(4 x + 1)^{2} (4 x - 1)^{2}

e^{\frac{x ^{2}}{x}} e^{3 x}

4.66 \cdot 1 0^{- 3}

What is e^{-at}t^{n-1} 1/(n!) ?
The solution to e^{-at}t^{n-1} 1/(n!) is (t^{n-1})/(e^{at)n!}