What is e^{-2x}(a+bx+cx^2) ?

The solution to e^{-2x}(a+bx+cx^2) is (cx^2+bx+a)/(e^{2x)}

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simplify e^{-2x}(a+bx+cx^2)

simplify

e^{- 2 x} (a + b x + c x^{2})

\frac{c x ^{2} + b x + a}{e ^{2 x}}

Solution steps

e^{- 2 x} (a + b x + c x^{2})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x}} (c x^{2} + b x + a)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( a + b x + c x ^{2} )}{e ^{2 x}}

1 \cdot (a + b x + c x^{2}) = a + b x + c x^{2}

= \frac{a + b x + c x ^{2}}{e ^{2 x}}

\frac{( 3 x y + 4 ) ^{2}}{y ^{2}}

3 x^{2} y^{2} (2 x y + 6 x^{2} y + 3)

5 (1 - x)^{- 1}

(10 v) (3 v^{4}) 3 v

What is e^{-2x}(a+bx+cx^2) ?
The solution to e^{-2x}(a+bx+cx^2) is (cx^2+bx+a)/(e^{2x)}