simplify (2^{40})^3

Solution

simplify

(2^{4 0^{\circ}})^{3}

8^{4 0^{\circ}}

Decimal Notation

4.27047 \dots

Solution steps

(2^{4 0^{\circ}})^{3}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{4 0^{\circ} \cdot 3}

Apply exponent rule:

a^{b x} = (a^{b})^{x}

2^{3 \cdot 4 0^{\circ}} = (2^{3})^{4 0^{\circ}}

= (2^{3})^{4 0^{\circ}}

2^{3} = 8

= 8^{4 0^{\circ}}

(e^{- l n ∣ x ∣})^{1}

(8 x^{3} y^{2}) (6 y^{3})

e^{- l n (8 x^{2})}

x^{- 7} d x

π r^{2} \cdot π r^{2}