What is \sqrt[3]{(5x^2-2x+4)^2} ?

The solution to \sqrt[3]{(5x^2-2x+4)^2} is (5x^2-2x+4)^{2/3}

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simplify \sqrt[3]{(5x^2-2x+4)^2}

simplify

(5 x^{2} - 2 x + 4)^{\frac{2}{3}}

Solution steps

Apply radical rule:

= ((5 x^{2} - 2 x + 4)^{2})^{\frac{1}{3}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (5 x^{2} - 2 x + 4)^{2 \cdot \frac{1}{3}}

2 \cdot \frac{1}{3} = \frac{2}{3}

= (5 x^{2} - 2 x + 4)^{\frac{2}{3}}

35 (35)

7.43 \cdot 1 0^{- 3}

e^{2 x} e^{3}

\frac{- 49}{7}

4.69 \cdot 1 0^{- 6}

What is \sqrt[3]{(5x^2-2x+4)^2} ?
The solution to \sqrt[3]{(5x^2-2x+4)^2} is (5x^2-2x+4)^{2/3}