What are the solutions to the equation 91n^2+49n=0 ?

The solutions to the equation 91n^2+49n=0 are n=0,n=-7/13

Find the zeros of 91n^2+49n=0

The zeros of 91n^2+49n=0 are n=0,n=-7/13

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91 n^{2} + 49 n = 0

n = 0, n = - \frac{7}{13}

Decimal Notation

n = 0, n = - 0.53846 \dots

Solution steps

91 n^{2} + 49 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 49 \pm 4 9 ^{2} - 4 \cdot 91 \cdot 0}{2 \cdot 91}

4 9^{2} - 4 \cdot 91 \cdot 0 = 49

n_{1, 2} = \frac{- 49 \pm 49}{2 \cdot 91}

Separate the solutions

n_{1} = \frac{- 49 + 49}{2 \cdot 91}, n_{2} = \frac{- 49 - 49}{2 \cdot 91}

n = \frac{- 49 + 49}{2 \cdot 91} : 0

n = \frac{- 49 - 49}{2 \cdot 91} : - \frac{7}{13}

The solutions to the quadratic equation are:

n = 0, n = - \frac{7}{13}

(2 - 3 i) (1 - i)

\frac{3 x}{2} - 3 x = \frac{- 5 x + 2}{2}

x^{3} - 6 x^{2} - 7 x

\frac{x}{3} - 2 = 7

(2 c)^{4}

What are the solutions to the equation 91n^2+49n=0 ?
The solutions to the equation 91n^2+49n=0 are n=0,n=-7/13
Find the zeros of 91n^2+49n=0
The zeros of 91n^2+49n=0 are n=0,n=-7/13