What is 10(0.8)^{-x} ?

The solution to 10(0.8)^{-x} is (10)/(0.8^x)

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simplify 10(0.8)^{-x}

simplify

10 (0.8)^{- x}

\frac{10}{0. 8 ^{x}}

Solution steps

10 \cdot 0. 8^{- x}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

0. 8^{- x} = \frac{1}{0. 8 ^{x}}

= 10 \cdot \frac{1}{0. 8 ^{x}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{10 \cdot 1}{0. 8 ^{x}}

Multiply the numbers:

10 \cdot 1 = 10

= \frac{10}{0. 8 ^{x}}

3.55 \cdot 1 0^{- 8}

215.51 \cdot 1 0^{- 3}

3.55 \cdot 1 0^{- 2}

(3 m n^{2}) (9 m^{2} n)

e^{- (- l n (\frac{5}{6}))^{0.5}}