What are the solutions to the equation 2a^2+11a-6=0 ?

The solutions to the equation 2a^2+11a-6=0 are a= 1/2 ,a=-6

Find the zeros of 2a^2+11a-6=0

The zeros of 2a^2+11a-6=0 are a= 1/2 ,a=-6

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2 a^{2} + 11 a - 6 = 0

a = \frac{1}{2}, a = - 6

Solution steps

2 a^{2} + 11 a - 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 6) = 13

a_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 11 + 13}{2 \cdot 2}, a_{2} = \frac{- 11 - 13}{2 \cdot 2}

a = \frac{- 11 + 13}{2 \cdot 2} : \frac{1}{2}

a = \frac{- 11 - 13}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

a = \frac{1}{2}, a = - 6

x^{3} - 2 x^{2} + x

\frac{1}{( 1 + 0.08 ) ^{1}}

∣ - 6 m ∣ = 30

(\frac{( - 5 )}{2})^{3}

(x + 0) (- 3 x + 1) < 0

What are the solutions to the equation 2a^2+11a-6=0 ?
The solutions to the equation 2a^2+11a-6=0 are a= 1/2 ,a=-6
Find the zeros of 2a^2+11a-6=0
The zeros of 2a^2+11a-6=0 are a= 1/2 ,a=-6