What is (a+b-c)^2(a-b+c)^2 ?

The solution to (a+b-c)^2(a-b+c)^2 is (a+b-c)^2(a+c-b)^2

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simplify (a+b-c)^2(a-b+c)^2

simplify

(a + b - c)^{2} (a - b + c)^{2}

(a + b - c)^{2} (a + c - b)^{2}

Solution steps

(a + b - c)^{2} (a - b + c)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(a + b - c)^{2} (a + c - b)^{2} = ((a + b - c) (a + c - b))^{2}

= ((a + b - c) (a + c - b))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (a + b - c)^{2} (a + c - b)^{2}

- 0.5 \cdot 1 0^{- 8}

b^{a}

\frac{e ^{x - 2 y}}{e ^{2 x + y}}

(5 y) (3 y^{2})

What is (a+b-c)^2(a-b+c)^2 ?
The solution to (a+b-c)^2(a-b+c)^2 is (a+b-c)^2(a+c-b)^2