What is (3j^{58}k^{26})(4j^{50}k^{41}) ?

The solution to (3j^{58}k^{26})(4j^{50}k^{41}) is 12j^{108}k^{67}

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simplify (3j^{58}k^{26})(4j^{50}k^{41})

simplify

(3 j^{58} k^{26}) (4 j^{50} k^{41})

12 j^{108} k^{67}

Solution steps

(3 j^{58} k^{26}) (4 j^{50} k^{41})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

j^{58} j^{50} = j^{58 + 50}

= 3 k^{26} \cdot 4 j^{58 + 50} k^{41}

Add the numbers:

58 + 50 = 108

= 3 k^{26} \cdot 4 j^{108} k^{41}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

k^{26} k^{41} = k^{26 + 41}

= 3 \cdot 4 j^{108} k^{26 + 41}

Add the numbers:

26 + 41 = 67

= 3 \cdot 4 j^{108} k^{67}

Multiply the numbers:

3 \cdot 4 = 12

= 12 j^{108} k^{67}

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What is (3j^{58}k^{26})(4j^{50}k^{41}) ?
The solution to (3j^{58}k^{26})(4j^{50}k^{41}) is 12j^{108}k^{67}