What are the solutions to the equation 0=x^2+4x+5 ?

The solutions to the equation 0=x^2+4x+5 are x=-2+i,x=-2-i

Find the zeros of 0=x^2+4x+5

The zeros of 0=x^2+4x+5 are x=-2+i,x=-2-i

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0 = x^{2} + 4 x + 5

x = - 2 + i, x = - 2 - i

Solution steps

0 = x^{2} + 4 x + 5

Switch sides

x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

x = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

x = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

x = - 2 + i, x = - 2 - i

\frac{11 e ^{9}}{22 e ^{10}}

5 x^{2} - 16 x + 3

x^{2} + 18 x + 32

n - 73 \geq 438

13 x^{2} - 37 = 0

What are the solutions to the equation 0=x^2+4x+5 ?
The solutions to the equation 0=x^2+4x+5 are x=-2+i,x=-2-i
Find the zeros of 0=x^2+4x+5
The zeros of 0=x^2+4x+5 are x=-2+i,x=-2-i