What is aRe^{-((ln(a))/b)R} ?

The solution to aRe^{-((ln(a))/b)R} is (aR}{e^{\frac{Rln(a))/b}}

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simplify aRe^{-((ln(a))/b)R}

simplify

a R e^{- (\frac{l n ( a )}{b}) R}

\frac{a R}{e ^{\frac{R l n ( a )}{b}}}

Solution steps

a R e^{- (\frac{l n ( a )}{b}) R}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= a \frac{1}{e ^{\frac{l n ( a )}{b} R}} R

\frac{1}{e ^{\frac{l n ( a )}{b} R}} = \frac{1}{e ^{\frac{R l n ( a )}{b}}}

= a \frac{1}{e ^{\frac{R l n ( a )}{b}}} R

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot a R}{e ^{\frac{l n ( a ) R}{b}}}

Multiply:

1 \cdot a = a

= \frac{a R}{e ^{\frac{l n ( a ) R}{b}}}

10 \cdot (6.023 \cdot 1 0^{23})

5 \cdot 4 + k^{2}

x^{2} (8 x)

3.37 \cdot 1 0^{- 9}

e^{x} e^{x^{2}}

What is aRe^{-((ln(a))/b)R} ?
The solution to aRe^{-((ln(a))/b)R} is (aR}{e^{\frac{Rln(a))/b}}