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Popular >

simplify e^{3ln(y)}e^{ln(u+1)}

Solution

simplify

e^{3 l n (y)} e^{l n (u + 1)}

Solution

y^{3} (u + 1)

Solution steps

e^{3 l n (y)} e^{l n (u + 1)}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{3 l n (y)} e^{l n (u + 1)} = e^{3 l n (y) + l n (u + 1)}

= e^{3 l n (y) + l n (u + 1)}

3 ln (y) + ln (u + 1) = ln (y^{3} (u + 1))

= e^{l n (y^{3} (u + 1))}

Apply log rule:

a^{l o g_{a} (b)} = b

= y^{3} (u + 1)

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Frequently Asked Questions (FAQ)

What is e^{3ln(y)}e^{ln(u+1)} ?
The solution to e^{3ln(y)}e^{ln(u+1)} is y^3(u+1)