What is 2sqrt(b-x)sqrt(b+x) ?

The solution to 2sqrt(b-x)sqrt(b+x) is 2sqrt((-x+b)(x+b))

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simplify 2sqrt(b-x)sqrt(b+x)

simplify

2 b - x b + x

2 (- x + b) (x + b)

Solution steps

2 b - x b + x

Apply radical rule:

a b = a \cdot b,

assuming

a \geq 0, b \geq 0

- x + b x + b = (- x + b) (x + b)

= 2 (- x + b) (x + b)

e^{- 2 t} cos (h) (t)

(9.6 x 1 0^{- 11}) (2 x 1 0^{17})

- e^{- \infty} (\infty + 1)

(1.6 \cdot 1 0^{- 19}) (0.016)

What is 2sqrt(b-x)sqrt(b+x) ?
The solution to 2sqrt(b-x)sqrt(b+x) is 2sqrt((-x+b)(x+b))