What is sqrt(\sqrt[5]{3x^{-4)}} ?

The solution to sqrt(\sqrt[5]{3x^{-4)}} is \sqrt[10]{3/(x^4)}

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simplify sqrt(\sqrt[5]{3x^{-4)}}

simplify

Solution steps

Apply radical rule:

= ((3 x^{- 4})^{\frac{1}{5}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (3 x^{- 4})^{\frac{1}{5} \cdot \frac{1}{2}}

\frac{1}{5} \cdot \frac{1}{2} = \frac{1}{10}

= (3 x^{- 4})^{\frac{1}{10}}

Multiply

3 x^{- 4} : \frac{3}{x ^{4}}

(1222.84) (1 + 0.01486)^{- 4}

e^{- 6} \cdot \frac{6 ^{3}}{3 !}

900 e^{- 900}

4.38 \cdot 1 0^{- 7}

What is sqrt(\sqrt[5]{3x^{-4)}} ?
The solution to sqrt(\sqrt[5]{3x^{-4)}} is \sqrt[10]{3/(x^4)}