What are the solutions to the equation x^2+13x-30=0 ?

The solutions to the equation x^2+13x-30=0 are x=2,x=-15

Find the zeros of x^2+13x-30=0

The zeros of x^2+13x-30=0 are x=2,x=-15

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x^{2} + 13 x - 30 = 0

x = 2, x = - 15

Solution steps

x^{2} + 13 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot (- 30) = 17

x_{1, 2} = \frac{- 13 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 17}{2 \cdot 1}, x_{2} = \frac{- 13 - 17}{2 \cdot 1}

x = \frac{- 13 + 17}{2 \cdot 1} : 2

x = \frac{- 13 - 17}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 2, x = - 15

x^{2} + x = 42

4 p^{2} - 4 p - 15 = 0

16 x^{2} - 169 y^{2}

9 t^{3} - 90 t^{2} + 144 t

(\frac{1}{3} - i \frac{2 5}{3} - \frac{1}{3})^{2}

What are the solutions to the equation x^2+13x-30=0 ?
The solutions to the equation x^2+13x-30=0 are x=2,x=-15
Find the zeros of x^2+13x-30=0
The zeros of x^2+13x-30=0 are x=2,x=-15