What is 0.3a^{-4}b^{-9}c^2 ?

The solution to 0.3a^{-4}b^{-9}c^2 is (0.3c^2)/(a^4b^9)

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simplify 0.3a^{-4}b^{-9}c^2

simplify

0.3 a^{- 4} b^{- 9} c^{2}

\frac{0.3 c ^{2}}{a ^{4} b ^{9}}

Solution steps

0.3 a^{- 4} b^{- 9} c^{2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

a^{- 4} = \frac{1}{a ^{4}}

= 0.3 \cdot \frac{1}{a ^{4}} b^{- 9} c^{2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

b^{- 9} = \frac{1}{b ^{9}}

= 0.3 \cdot \frac{1}{a ^{4}} \cdot \frac{1}{b ^{9}} c^{2}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{0.3 \cdot 1 \cdot 1 \cdot c ^{2}}{a ^{4} b ^{9}}

Multiply the numbers:

0.3 \cdot 1 \cdot 1 = 0.3

= \frac{0.3 c ^{2}}{a ^{4} b ^{9}}

3 e^{3 - 3 t} \cdot e^{- jnπ t}

2.03 \cdot 1 0^{- 5}

3 a^{2}^{2}

50 (1.54)^{- 5 (2)}

1.15 \cdot 1 0^{- 10}

What is 0.3a^{-4}b^{-9}c^2 ?
The solution to 0.3a^{-4}b^{-9}c^2 is (0.3c^2)/(a^4b^9)