What is e^{-cz}sin(ax)cos(by) ?

The solution to e^{-cz}sin(ax)cos(by) is (sin(ax)cos(by))/(e^{cz)}

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simplify e^{-cz}sin(ax)cos(by)

simplify

e^{- cz} sin (a x) cos (b y)

\frac{sin ( a x ) cos ( b y )}{e ^{cz}}

Solution steps

e^{- cz} sin (a x) cos (b y)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{cz}} sin (a x) cos (b y)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( a x ) cos ( b y )}{e ^{cz}}

Multiply:

1 \cdot sin (a x) = sin (a x)

= \frac{sin ( a x ) cos ( b y )}{e ^{cz}}

825 (3.3 \cdot 1 0^{- 3})

\frac{x - 8}{8 - x}

2.67 \cdot 1 0^{- 6}

1.27 x 1 0^{- 1}

2.67 \cdot 1 0^{- 7}

What is e^{-cz}sin(ax)cos(by) ?
The solution to e^{-cz}sin(ax)cos(by) is (sin(ax)cos(by))/(e^{cz)}