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Popular >

simplify e^{-ln|2z^2+2|}

Solution

simplify

e^{- l n ∣ 2 z^{2} + 2 ∣}

Solution

\frac{1}{∣ 2 z ^{2} + 2 ∣}

Solution steps

e^{- l n ∣ 2 z^{2} + 2 ∣}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n ∣ 2 z^{2} + 2 ∣}}

e^{l n ∣ 2 z^{2} + 2 ∣} = 2 z^{2} + 2

= \frac{1}{∣ 2 z ^{2} + 2 ∣}

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Frequently Asked Questions (FAQ)

What is e^{-ln|2z^2+2|} ?
The solution to e^{-ln|2z^2+2|} is 1/(|2z^2+2|)