What is 3.2*10^{-19}*0.5 ?

The solution to 3.2*10^{-19}*0.5 is 1/(5^{20)*65536}

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simplify 3.210^{-19}0.5

simplify

3.2 \cdot 1 0^{- 19} \cdot 0.5

\frac{1}{5 ^{20} \cdot 65536}

Decimal Notation

1.6 E - 19

Solution steps

3.2 \cdot 1 0^{- 19} \cdot 0.5

Multiply the numbers:

3.2 \cdot 0.5 = 1.6

= 1.6 \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 1.6

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 1.6

\frac{1}{1 0 ^{19}} \cdot 1.6 = \frac{1.6}{1 0 ^{19}}

= \frac{1.6}{1 0 ^{19}}

\frac{1.6}{1 0 ^{19}} = \frac{16}{10 \cdot 1 0 ^{19}}

= \frac{16}{10 \cdot 1 0 ^{19}}

10 \cdot 1 0^{19} = 1 0^{20}

= \frac{16}{1 0 ^{20}}

Factor the number:

16 = 2^{4}

= \frac{2 ^{4}}{1 0 ^{20}}

Factor

1 0^{20} : 2^{20} \cdot 5^{20}

= \frac{2 ^{4}}{2 ^{20} \cdot 5 ^{20}}

\frac{2 ^{4}}{2 ^{20}} = \frac{1}{2 ^{16}}

= \frac{1}{2 ^{16} \cdot 5 ^{20}}

2^{16} = 65536

= \frac{1}{5 ^{20} \cdot 65536}

(a + b) \cdot e^{- s t}

5 (22)

e^{- 3 l m x}

5.17 \cdot (4.15 \cdot 1 0^{- 3})

171.46 e^{- (0.012 \cdot 180)}