What is e^{-(1+0.5x)^{-2}} ?

The solution to e^{-(1+0.5x)^{-2}} is 1/(e^{\frac{1){(0.5x+1)^2}}}

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simplify e^{-(1+0.5x)^{-2}}

simplify

e^{- (1 + 0.5 x)^{- 2}}

\frac{1}{e ^{\frac{1}{( 0.5 x + 1 ) ^{2}}}}

Solution steps

e^{- (1 + 0.5 x)^{- 2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(1 + 0.5 x)^{- 2}}}

e^{(1 + 0.5 x)^{- 2}} = e^{\frac{1}{( 1 + 0.5 x ) ^{2}}}

= \frac{1}{e ^{\frac{1}{( 1 + 0.5 x ) ^{2}}}}

\frac{( - 3 n + 6 ) ^{2}}{n ^{2}}

0.65 \cdot 1 0^{- 1}

- e^{- l n (9)}

\frac{8 ^{13}}{3 ^{13}}

a b^{2} \cdot (a b^{10})

What is e^{-(1+0.5x)^{-2}} ?
The solution to e^{-(1+0.5x)^{-2}} is 1/(e^{\frac{1){(0.5x+1)^2}}}