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Popular >

simplify e^{-ln^2(1/2)}

Solution

simplify

e^{- l n^{2} (\frac{1}{2})}

Solution

\frac{1}{e ^{l n^{2} (2)}}

+1

Decimal Notation

0.61850 \dots

Solution steps

e^{- l n^{2} (\frac{1}{2})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n^{2} (\frac{1}{2})}}

e^{l n^{2} (\frac{1}{2})} = e^{l n^{2} (2)}

= \frac{1}{e ^{l n^{2} (2)}}

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Frequently Asked Questions (FAQ)

What is e^{-ln^2(1/2)} ?
The solution to e^{-ln^2(1/2)} is 1/(e^{ln^2(2))}