What are the solutions to the equation 6+9z+z^2=0 ?

The solutions to the equation 6+9z+z^2=0 are z=(-9+sqrt(57))/2 ,z=(-9-sqrt(57))/2

Find the zeros of 6+9z+z^2=0

The zeros of 6+9z+z^2=0 are z=(-9+sqrt(57))/2 ,z=(-9-sqrt(57))/2

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6 + 9 z + z^{2} = 0

z = \frac{- 9 + 57}{2}, z = \frac{- 9 - 57}{2}

Solution steps

6 + 9 z + z^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

z^{2} + 9 z + 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 6 = 57

z_{1, 2} = \frac{- 9 \pm 57}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 9 + 57}{2 \cdot 1}, z_{2} = \frac{- 9 - 57}{2 \cdot 1}

z = \frac{- 9 + 57}{2 \cdot 1} : \frac{- 9 + 57}{2}

z = \frac{- 9 - 57}{2 \cdot 1} : \frac{- 9 - 57}{2}

The solutions to the quadratic equation are:

z = \frac{- 9 + 57}{2}, z = \frac{- 9 - 57}{2}

0 = 3 x + 4

4 x^{2} + 9 x^{4}

x^{2} - 2 x > 0

(2 c d)^{2} (- 4 c^{3})^{2}

(\frac{2}{3} h^{3})^{4}

What are the solutions to the equation 6+9z+z^2=0 ?
The solutions to the equation 6+9z+z^2=0 are z=(-9+sqrt(57))/2 ,z=(-9-sqrt(57))/2
Find the zeros of 6+9z+z^2=0
The zeros of 6+9z+z^2=0 are z=(-9+sqrt(57))/2 ,z=(-9-sqrt(57))/2