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Popular >

simplify (d^0+e^0)(d^0+e^0)

Solution

simplify

(d^{0} + e^{0}) (d^{0} + e^{0})

Solution

4

Solution steps

(d^{0} + e^{0}) (d^{0} + e^{0})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(d^{0} + e^{0}) (d^{0} + e^{0}) = (d^{0} + e^{0})^{1 + 1}

= (d^{0} + e^{0})^{1 + 1}

Add the numbers:

1 + 1 = 2

= (d^{0} + e^{0})^{2}

Apply rule

a^{0} = 1, a \neq = 0

d^{0} = 1, e^{0} = 1

= (1 + 1)^{2}

Add the numbers:

1 + 1 = 2

= 2^{2}

2^{2} = 4

= 4

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Frequently Asked Questions (FAQ)

What is (d^0+e^0)(d^0+e^0) ?
The solution to (d^0+e^0)(d^0+e^0) is 4