What is (\sqrt[5]{10x})^{4^'} ?

The solution to (\sqrt[5]{10x})^{4^'} is 10^{(4^')/5}x^{(4^')/5}

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simplify (\sqrt[5]{10x})^{4^'}

simplify

1 0^{\frac{4 ^{'}}{5}} x^{\frac{4 ^{'}}{5}}

Solution steps

Apply radical rule:

= ((10 x)^{\frac{1}{5}})^{4^{^{^{'}}}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (10 x)^{\frac{1}{5} \cdot 4^{^{^{'}}}}

Simplify

\frac{1}{5} \cdot 4^{^{'}} : \frac{4 ^{^{'}}}{5}

= (10 x)^{\frac{4 ^{^{'}}}{5}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 1 0^{\frac{4 ^{^{^{'}}}}{5}} x^{\frac{4 ^{^{^{'}}}}{5}}

3 729 y - 6^{\frac{1}{2}}

175 \cdot 0.000693 \cdot 1 0^{- 3}

((- \frac{4}{3})^{'})^{- 2}

e^{- y} \cdot (2 e^{2 y})

What is (\sqrt[5]{10x})^{4^'} ?
The solution to (\sqrt[5]{10x})^{4^'} is 10^{(4^')/5}x^{(4^')/5}