What are the solutions to the equation b^2+60=8 ?

The solutions to the equation b^2+60=8 are b=2sqrt(13)i,b=-2sqrt(13)i

Find the zeros of b^2+60=8

The zeros of b^2+60=8 are b=2sqrt(13)i,b=-2sqrt(13)i

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b^{2} + 60 = 8

b = 213 i, b = - 213 i

Solution steps

b^{2} + 60 = 8

Move

60

to the right side

b^{2} = - 52

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = - 52, b = - - 52

- 52 = 213 i

- - 52 = - 213 i

b = 213 i, b = - 213 i

- 3 x^{2} + 4 x - 1

r^{2} + 9 r + 20

\frac{1}{2} \cdot \frac{5}{4}

8 \cdot \frac{15}{5} - (5 + 9)

∣ x - 4 ∣ \geq x^{2} - 7 x + 12

What are the solutions to the equation b^2+60=8 ?
The solutions to the equation b^2+60=8 are b=2sqrt(13)i,b=-2sqrt(13)i
Find the zeros of b^2+60=8
The zeros of b^2+60=8 are b=2sqrt(13)i,b=-2sqrt(13)i