What is p^1(1,3,5)p^2(2,-1,4) ?

The solution to p^1(1,3,5)p^2(2,-1,4) is (1*3*5,,)(2,-1*4,)p^3

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simplify p^1(1,3,5)p^2(2,-1,4)

simplify

p^{1} (1, 3, 5) p^{2} (2, - 1, 4)

(1 \cdot 3 \cdot 5,,) (2, - 1 \cdot 4,) p^{3}

Solution steps

p^{1} (1, 3, 5) p^{2} (2, - 1, 4)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

p^{1} p^{2} = p^{1 + 2}

= (1, 3, 5) p^{1 + 2} (2, - 1, 4)

Add the numbers:

1 + 2 = 3

= (1, 3, 5) p^{3} (2, - 1, 4)

e^{- 0.0683}

2 π^{8.85} \cdot 1 0^{- 12}

30 \cdot (10) e^{2 - 1} (- 1) e^{2}

What is p^1(1,3,5)p^2(2,-1,4) ?
The solution to p^1(1,3,5)p^2(2,-1,4) is (1*3*5,,)(2,-1*4,)p^3