What is (e^{(hv)/(kT)}-1)^{-1} ?

The solution to (e^{(hv)/(kT)}-1)^{-1} is 1/(e^{\frac{hv){kT}}-1}

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simplify (e^{(hv)/(kT)}-1)^{-1}

simplify

(e^{\frac{h v}{k T}} - 1)^{- 1}

\frac{1}{e ^{\frac{h v}{k T}} - 1}

Solution steps

(e^{\frac{h v}{k T}} - 1)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{( e ^{\frac{h v}{k T}} - 1 )}

Remove parentheses:

(a) = a

= \frac{1}{e ^{\frac{h v}{k T}} - 1}

(\frac{2}{9}) e^{- 1}

x^{- \frac{5}{2} = 32}

(5 x^{9}) (4 x^{5})

What is (e^{(hv)/(kT)}-1)^{-1} ?
The solution to (e^{(hv)/(kT)}-1)^{-1} is 1/(e^{\frac{hv){kT}}-1}